x^2+9.5^2=19.3^2

Solution for x^2+9.5^2=19.3^2 equation:

x^2+9.5^2=19.3^2

We move all terms to the left:

x^2+9.5^2-(19.3^2)=0

We add all the numbers together, and all the variables

x^2-282.24=0

a = 1; b = 0; c = -282.24;
Δ = b2-4ac
Δ = 02-4·1·(-282.24)
Δ = 1128.96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{1128.96}}{2*1}=\frac{0-\sqrt{1128.96}}{2}
=-\frac{\sqrt{}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{1128.96}}{2*1}=\frac{0+\sqrt{1128.96}}{2}
=\frac{\sqrt{}}{2}
$